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Lecture 14

THE MAIN SEQUENCE


Key Concepts


(1) The internal structure of a star is determined by four simple physical laws.

You can't construct a star with arbitrary size: a star is forced to obey the laws of nature.
Divide a star into layers, like an onion. The four laws which dictate a star's structure tell us what the density, temperature, pressure, energy generation rate, and so forth must be within each layer, or shell. The four laws which dictate the structure can be written in mathematical form, so they can be used to create mathematical models which give numerical values for the density, etc. within each shell.


LAW ONE:
The Law of Hydrostatic Equilibrium

This is a law we've encountered before. It simply states that within every layer, the outward force of pressure equals the inward force of gravity.


LAW TWO:
The Law of Energy Transport

Again, a law that we've encountered before. It states that within every layer, energy is transported outward (from the hotter center to the cooler surface) by radiation, convection, or conduction. The rate of energy transport follows known mathematical laws. For instance, the rate of radiation transport depends on the temperature, density, and opacity within a layer.


LAW THREE:
The Continuity of Mass Law

This is the most absurdly simpleminded of the laws. It states that the total mass of a star equals the sum of the masses of the individual layers. Moreover, there are no gaps between layers: each layer rests directly on top of the one below.


LAW FOUR:
The Continuity of Energy Law

This is nearly as simpleminded as the previous law. It states that the total luminosity of a star equals the sum of the luminosities of the individual layers. Every layer in which fusion occurs has a luminosity. Since only the central layers, where the density and temperature is high, have fusion occuring within them, most of a star's luminosity comes from the inner layers.


Since the four laws can be expressed as mathematical equations (which I won't write down, since they involve differential calculus), they can be solved numerically to yield tables of density, temperature, pressure, and so forth, for each layer of the star.

Generally, the equations must be solved on a computer (too complex to be done with paper and pencil in a reasonable time). We ought to remember the basic law of computers:
GIGO - Garbage In, Garbage Out.
The results which we get from out equations are only as good as the assumptions which go into them. If we assume that the Sun is powered by an enormous gerbil running on a treadmill, our results will be garbage, no matter how big the computer, or how fancy the computer program.


From time to time, it's a good idea to
QUESTION YOUR BASIC ASSUMPTIONS!


Example of a computer model: The Sun
The observed surface temperature is 5800 Kelvin. The computed central temperature is 14.6 million Kelvin.


(2) Stars must have M < 60sun to be stable; they must have M > 0.08 Msun to fuse hydrogen.

The main sequence has a cutoff at the high mass and low mass end. Very few stars are observed with masses greater than 50 times that of the Sun or with masses less than 1/10 that of the Sun. Why?


There exists a high-mass cutoff because very high mass stars cannot attain hydrostatic equilibrium. Very high mass stars produce enormous numbers of high-energy photons (L and T are both large). Photons exert pressure on gas (an effect called radiation pressure.) Ordinarily, the effects of radiation pressure are small, but for stars with M > 60 Msun, models indicate, the radiation pressure is large enough to blow the star apart!


There exists a low-mass cutoff to the main sequence because gaseous spheres with M <0.08sun, models indicate, have central temperatures too low for fusion of hydrogen to helium to take place. These low-mass gaseous spheres are not called ``stars'', but ``brown dwarfs''. (The name ``star'' is reserved for objects which are powered by nuclear fusion.)

Stars shine because they are hot; brown dwarfs also shine (albeit dimly) because they are hot (albeit not very hot). Brown dwarfs radiate in the infrared, powered by their gradual graviational collapse (think of them as protostars in which fusion has failed to stop the collapse). Brown dwarfs can be observed. Searching for a brown dwarf at random locations in the galaxy is like searching for a very dim needle in a very big haystack. Some success has been attained in looking for brown dwarfs in binary systems with stars:

The above illustration shows two images of the star Gliese 229A and its brown dwarf companion, Gliese 229B. (Click on the image for a larger version). The image on the left was taken from the ground, using a 60-inch telescope on Mount Palomar, in Southern California. The higher-resolution image on the right was taken using the Hubble Space Telescope. Although Gliese 229A is off the edge of the Space Telescope image to the left, it is so bright that it floods the telescope's detector. The tiny speck on the right is the brown dwarf. The diagonal line is a diffraction spike caused by scattered light in the telescope's optics. The mass of the brown dwarf Gliese 229B is 0.02 M
sun, or about 20 times the mass of Jupiter.
(Image credit: S. Kulkarni [Caltech], D. Golimowski [Johns Hopkins], and NASA)


(3) High-mass stars have a short lifetime on the main sequence; low-mass stars have a long lifetime.

High mass stars require high central pressures to maintain hydrostatic equilibrium.
High central pressures imply high central density and temperature.
High central density and temperature imply VERY high fusion rates.
Very high fusion rates imply short lifetimes, because the star's fuel supply (its hydrogen) will be rapidly exhausted.

A star's lifetime is:
t = M / L
(when the lifetime t, the mass M, and the luminosity L are all expressed in solar units)

It is observed that a star's luminosity depends strongly on its mass:
L = M
3.5

Therefore, the dependence of lifetime on mass is:
t = M / M
3.5 = 1 / M2.5

In the example given by the textbook, increasing the mass of a star by a factor of 4 decreases the lifetime by a factor of 1/32.


Examples of main sequence lifetimes:

The Sun:
M = 1 M
sun
t = 1 t
sun = 10 billion years

M-type star:
M = 0.2 M
sun
t = 1/(0.2)
2.5 tsun = 56 tsun = 560 billion years

O-type star:
M = 40 M
sun
t = 1/(40)
2.5 tsun = 0.0001 tsun = 1 million years

The main sequence lifetime of an M star is comfortably longer than the age of the universe (about 15 billion years). Thus, every M-type main sequence star that has ever been created is still chugging away, converting hydrogen into helium in its core. On the other hand, every O-type main sequence star in existence must be very young (under a million years old). Massive stars are like James Dean: they live fast, die young in a blaze of glory, and (as we shall see later in the course) leave a badly crushed corpse.


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